Remove the sqrt(2) normalisation from the scalar longitudinal mode
Following from lalsuite!910 (merged) (cc @max-isi) the sqrt(2) normalisation should be removed from the scalar longitudinal mode's response, to agree with the normalisation of the other modes and make Fb = -Fl.
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I'll defer to @max-isi here. I know the link Nishizawa paper does have the sqrt(2) in it, but I've also seen papers that say Fb = -Fl, which you do not get if you include the sqrt(2) factor.
Hi @sylvia.biscoveanu this comes down to the definition of the polarization amplitudes.
We usually write the detector output as
h = F^A h_A, with an implicit sum over polarizationsAand the response defined asF_A = e^A_{ab} D^{ab}for polarization tensorse^Aand detector tensorD^{ab}. Furthermore, we usually want the polarization amplitudesh_Ato correspond to the metric components in some standard (synchronous) gauge, $h_{ab} = h_A e^{A}_{ab}
. In particular for the longitudinal mode (\ell
$), this means (picking a frame)h_{zz} = h_\elland there's no\sqrt{2}that appears anywhere. (This might become clearer if you look at Sect. IIA in http://arxiv.org/abs/1710.03794)Now, we are free to redefine the polarization tensors and amplitudes however we want, but everything must be kept consistent in the expression for the detector output
h. For example, like Nishizawa and other theorists, we can use this freedom to enforce thate^{\ell}_{ab}have the same norm as the other polarization tensors (note, e.g., thate^{+}_{ab} e^{+}{}^{ab} = 2, whilee^{\ell}_{ab} e^{\ell}{}^{ab} = 1). That is, we can redefinee^{\ell}_{ab} \rightarrow \sqrt{2} e^{\ell}_{ab}to gete^{\ell}_{ab} e^{\ell}{}^{ab} = 2. However, this comes at the price of either modifying what you mean byh_{\ell} \rightarrow h_\ell / \sqrt{2}, or changing the detector output expression to beh = \sum_{A\neq \ell}F^A h_A + F^\ell h_\ell / \sqrt{2}. So it's annoying.This is all to say that the
\sqrt{2}I introduced amounted to a redefinition of the longitudinal polarization amplitude that means it's no longer theh_{zz}metric component as one would expect (like for the other polarizations) buth_{zz}/\sqrt{2}, and you end up withF_b \neq - F_\ellartificially.Edited by Max Isi- Resolved by Gregory Ashton
@matthew-pitkin is this ready to be merged?
changed milestone to %0.5.5
mentioned in commit 75bb453d