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Remove the sqrt(2) normalisation from the scalar longitudinal mode

Merged Matthew Pitkin requested to merge matthew-pitkin/bilby:scalar-fix into master
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Following from lalsuite!910 (merged) (cc @max-isi) the sqrt(2) normalisation should be removed from the scalar longitudinal mode's response, to agree with the normalisation of the other modes and make Fb = -Fl.

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  • Moritz Huebner approved this merge request

    approved this merge request

  • I'm looking at the LALInference MR and wondering why @max-isi says it was originally introduced incorrectly? For example, Eq. 1 here also has this factor of sqrt(2).

  • I'll defer to @max-isi here. I know the link Nishizawa paper does have the sqrt(2) in it, but I've also seen papers that say Fb = -Fl, which you do not get if you include the sqrt(2) factor.

  • Hi @sylvia.biscoveanu this comes down to the definition of the polarization amplitudes.

    We usually write the detector output as

    h = F^A h_A
    , with an implicit sum over polarizations
    A
    and the response defined as
    F_A = e^A_{ab} D^{ab}
    for polarization tensors
    e^A
    and detector tensor
    D^{ab}
    . Furthermore, we usually want the polarization amplitudes
    h_A
    to correspond to the metric components in some standard (synchronous) gauge, $h_{ab} = h_A e^{A}_{ab}
    . In particular for the longitudinal mode (
    \ell$), this means (picking a frame)
    h_{zz} = h_\ell
    and there's no
    \sqrt{2}
    that appears anywhere. (This might become clearer if you look at Sect. IIA in http://arxiv.org/abs/1710.03794)

    Now, we are free to redefine the polarization tensors and amplitudes however we want, but everything must be kept consistent in the expression for the detector output

    h
    . For example, like Nishizawa and other theorists, we can use this freedom to enforce that
    e^{\ell}_{ab}
    have the same norm as the other polarization tensors (note, e.g., that
    e^{+}_{ab} e^{+}{}^{ab} = 2
    , while
    e^{\ell}_{ab} e^{\ell}{}^{ab} = 1
    ). That is, we can redefine
    e^{\ell}_{ab} \rightarrow \sqrt{2} e^{\ell}_{ab}
    to get
    e^{\ell}_{ab} e^{\ell}{}^{ab} = 2
    . However, this comes at the price of either modifying what you mean by
    h_{\ell} \rightarrow h_\ell / \sqrt{2}
    , or changing the detector output expression to be
    h = \sum_{A\neq \ell}F^A h_A + F^\ell h_\ell / \sqrt{2}
    . So it's annoying.

    This is all to say that the

    \sqrt{2}
    I introduced amounted to a redefinition of the longitudinal polarization amplitude that means it's no longer the
    h_{zz}
    metric component as one would expect (like for the other polarizations) but
    h_{zz}/\sqrt{2}
    , and you end up with
    F_b \neq - F_\ell
    artificially.

    Edited by Max Isi
  • Gregory Ashton changed milestone to %0.5.5

    changed milestone to %0.5.5

  • Gregory Ashton approved this merge request

    approved this merge request

  • Gregory Ashton resolved all threads

    resolved all threads

  • Gregory Ashton mentioned in commit 75bb453d

    mentioned in commit 75bb453d

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